A) \[{{x}^{2}}+{{y}^{2}}-2x-2y+1=0\]
B) \[{{x}^{2}}+{{y}^{2}}-x-y=0\]
C) \[2{{x}^{2}}+2{{y}^{2}}-3x-3y+1=0\]
D) \[{{x}^{2}}+{{y}^{2}}-3x-3y+2=0\]
Correct Answer: B
Solution :
The radius will be minimum, if the given points are the end points of a diameter.
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