A) \[\pi {{a}^{2}}\]
B) \[2\pi {{a}^{2}}\]
C) \[4\pi {{a}^{2}}\]
D) \[\frac{1}{2}\pi {{a}^{2}}\]
Correct Answer: A
Solution :
\[{{x}^{2}}+{{y}^{2}}-2ax=0\] Obviously, radius of the circle is a. Hence the area of triangle is \[\pi {{a}^{2}}\].
You need to login to perform this action.
You will be redirected in
3 sec
