A) 2
B) \[\sqrt{2}\]
C) 3
D) \[2\sqrt{2}\]
Correct Answer: B
Solution :
Equation of the circle is \[(x-1)(x-3)+(y-2)(y-4)=0\] So, radius\[=\frac{1}{2}\sqrt{{{(3-1)}^{2}}+{{(4-2)}^{2}}}=\frac{1}{2}\sqrt{8}=\frac{2\sqrt{2}}{2}=\sqrt{2}\].
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