A) \[{{x}^{2}}+{{y}^{2}}-2x+2y-47=0\]
B) \[{{x}^{2}}+{{y}^{2}}-2x+2y+47=0\]
C) \[{{x}^{2}}+{{y}^{2}}+2x-2y-47=0\]
D) None of these
Correct Answer: A
Solution :
Centre is \[(1,\,-1)\] (point of intersection of two given lines) and \[\pi {{r}^{2}}=154\Rightarrow \,r=7\] \[\therefore \] Equation of required circle is \[{{(x-1)}^{2}}\,+{{(y+1)}^{2}}=49\] \[\Rightarrow \,\]\[{{x}^{2}}+{{y}^{2}}-2x+2y-47=0.\]
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