A) \[{{x}^{2}}+{{y}^{2}}-4x-2y+5=0\]
B) \[{{x}^{2}}+{{y}^{2}}-4x-2y-5=0\]
C) \[{{x}^{2}}+{{y}^{2}}-4x-2y+4=0\]
D) \[{{x}^{2}}+{{y}^{2}}-4x-2y-4=0\]
Correct Answer: C
Solution :
Centre: (2, 1) Radius is distance of point (2, 1) from \[3x+4y=5\] i.e., \[\left| \frac{3.2+4.1-5}{\sqrt{9+16}} \right|\Rightarrow \left| \frac{6+4-5}{5} \right|=1\] \ circle is \[{{(x-2)}^{2}}+{{(y-1)}^{2}}=1\] \[{{x}^{2}}+{{y}^{2}}-4x-2y+4=0\].
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