JEE Main & Advanced Mathematics Circle and System of Circles Question Bank Equations of circle, Geometrical problems regarding circle

  • question_answer
     The radius of the circle \[{{x}^{2}}+{{y}^{2}}+4x+6y+13=0\] is  [Karnataka CET 2005]

    A)             \[\sqrt{26}\]                          

    B)             \[\sqrt{13}\]

    C)             \[\sqrt{23}\]                          

    D)             0

    Correct Answer: D

    Solution :

               Given equation of circle is                    \[{{x}^{2}}+{{y}^{2}}+4x+6y+13=0\]                     Radius = \[\sqrt{{{g}^{2}}+{{f}^{2}}-c}=\sqrt{4+9-13}=0\].


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