A) \[{{x}^{2}}+{{y}^{2}}+2x-2y=62\]
B) \[{{x}^{2}}+{{y}^{2}}-2x+2y=47\]
C) \[{{x}^{2}}+{{y}^{2}}+2x-2y=47\]
D) \[{{x}^{2}}+{{y}^{2}}-2x+2y=62\]
Correct Answer: B
Solution :
Centre of circle = Point of intersection of diameters = (1, ?1) Now area \[=154\Rightarrow \pi {{r}^{2}}=154\Rightarrow r=7\] Hence the equation of required circle is \[{{(x-1)}^{2}}+{{(y+1)}^{2}}={{7}^{2}}\Rightarrow {{x}^{2}}+{{y}^{2}}-2x+2y=47\].
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