A) \[{{x}^{2}}+{{y}^{2}}-2x-2y+1=0\]
B) \[{{x}^{2}}+{{y}^{2}}-2x-2y-1=0\]
C) \[{{x}^{2}}+{{y}^{2}}-2x-2y=0\]
D) None of these
Correct Answer: A
Solution :
Circle is \[{{x}^{2}}+{{y}^{2}}-2x-2y+1=0\]as centre is (1, 1) and radius = 1.
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