A) \[{{x}^{2}}+{{y}^{2}}-2x+4y+3=0\]
B) \[{{x}^{2}}+{{y}^{2}}-2x+4y-3=0\]
C) \[{{x}^{2}}+{{y}^{2}}+2x-4y-3=0\]
D) \[{{x}^{2}}+{{y}^{2}}+2x-4y+3=0\]
Correct Answer: A
Solution :
According to the question, the required circle passes through (0,?1). Therefore, the radius is the distance between the points (0, ?1) and (1, ?2) i.e., \[\sqrt{2}\]. Hence the equation is \[{{(x-1)}^{2}}+{{(y+2)}^{2}}={{(\sqrt{2})}^{2}}\] \[\Rightarrow {{x}^{2}}+{{y}^{2}}-2x+4y+3=0\] Trick : Since this is the only circle passing through (0, ?1).
You need to login to perform this action.
You will be redirected in
3 sec
