A) \[g=f=r\]
B) \[g=f=c=r\]
C) \[g=f=\sqrt{c}=r\]
D) \[g=f\] and \[{{c}^{2}}=r\]
Correct Answer: C
Solution :
Conditions are \[g=f=r\] and\[\sqrt{{{g}^{2}}+{{f}^{2}}-c}=r\] \[\Rightarrow g=\sqrt{c}\].
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