A) \[g=f\]
B) \[{{g}^{2}}=c\]
C) \[{{f}^{2}}=c\]
D) \[{{g}^{2}}+{{f}^{2}}=c\]
Correct Answer: B
Solution :
Touches x-axis, hence radius = ordinate of centre. Hence \[\sqrt{{{g}^{2}}+{{f}^{2}}-c}=(-f)\] or \[{{g}^{2}}=c\].
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