A) \[{{(x-2)}^{2}}+{{(y-3)}^{2}}=8\]
B) \[{{(x-2)}^{2}}+{{(y-3)}^{2}}=3\]
C) \[{{(x+2)}^{2}}+{{(y+3)}^{2}}=2\sqrt{2}\]
D) \[{{(x-2)}^{2}}+{{(y-3)}^{2}}=2\sqrt{2}\]
Correct Answer: A
Solution :
Find the radius by finding perpendicular distance from centre of the circle on the tangent and then find the equation of circle.
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