A) \[{{x}^{2}}+{{y}^{2}}+8x-6y+9=0\]
B) \[{{x}^{2}}+{{y}^{2}}+8x+6y-11=0\]
C) \[{{x}^{2}}+{{y}^{2}}+8x+6y-9=0\]
D) None of these
Correct Answer: A
Solution :
Centre is \[(-4,\ 3)\] Radius = Distance between centres ? Radius of other circle \[=5-1=4\] Hence equation of circle is \[{{x}^{2}}+{{y}^{2}}+8x-6y+9=0\]. Trick: Only option (a) has centre (?4, 3).
You need to login to perform this action.
You will be redirected in
3 sec
