JEE Main & Advanced Mathematics Circle and System of Circles Question Bank Equations of circle, Geometrical problems regarding circle

  • question_answer
    Locus of the centre of the circle touching both the co-ordinates axes is

    A)            \[{{x}^{2}}+{{y}^{2}}=0\]

    B)            \[{{x}^{2}}+{{y}^{2}}=\]a non-zero constant

    C)            \[{{x}^{2}}-{{y}^{2}}=0\]

    D)            \[{{x}^{2}}-{{y}^{2}}=\]a non-zero constant

    Correct Answer: C

    Solution :

               As centres lie on angle bisectors of co-ordinate axes or \[x=0\] and \[y=0,\] we get two lines which are perpendicular to each other on which the centres lie i.e. \[x=y\] and \[x=-y\] or \[{{x}^{2}}-{{y}^{2}}=0\] as combined equation.


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