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JEE Main & Advanced Mathematics Circle and System of Circles Question Bank Equations of circle, Geometrical problems regarding circle

  • question_answer
     Radius of the circle \[{{x}^{2}}+{{y}^{2}}+2x\cos \theta \] \[+2y\sin \theta -8=0\], is [MNR 1974]

    A)            1    

    B)            3

    C)            \[2\sqrt{3}\]                             

    D)            \[\sqrt{10}\]

    Correct Answer: B

    Solution :

               \[R=\sqrt{{{\cos }^{2}}\theta +{{\sin }^{2}}\theta +8}=3\]


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