A) \[{{x}^{2}}+{{y}^{2}}+4x-2y-35=0\]
B) \[{{x}^{2}}+{{y}^{2}}-4x+2y+35=0\]
C) \[{{x}^{2}}+{{y}^{2}}+4x+2y+35=0\]
D) None of these
Correct Answer: A
Solution :
Centre (-2, 1), radius \[=\sqrt{36+4}=\sqrt{40}\] Hence equation of circle is \[{{x}^{2}}+{{y}^{2}}+4x-2y-35=0\].
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