A) \[{{x}^{2}}+{{y}^{2}}+4x+4y-5=0\]
B) \[{{x}^{2}}+{{y}^{2}}-4x-4y-5=0\]
C) \[{{x}^{2}}+{{y}^{2}}-4x=13\]
D) \[{{x}^{2}}+{{y}^{2}}-4x-4y+5=0\]
Correct Answer: B
Solution :
Given that centre of circle is (2, 2) Since circle is passing from point (4, 5) So, radius of circle \[=\sqrt{{{(4-2)}^{2}}+{{(5-2)}^{2}}}\]\[=\sqrt{(4+9)}=\sqrt{13}\] Therefore, equation of circle is \[{{(x-2)}^{2}}+{{(y-2)}^{2}}={{(\sqrt{13})}^{2}}\] or \[{{x}^{2}}-4x+4+{{y}^{2}}-4y+4=13\] or \[{{x}^{2}}+{{y}^{2}}-4x-4y-5=0\].
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