A) \[{{x}^{2}}+{{y}^{2}}+8x+2y+51=0\]
B) \[{{x}^{2}}+{{y}^{2}}+8x-2y-51=0\]
C) \[{{x}^{2}}+{{y}^{2}}+8x+2y-51=0\]
D) \[{{x}^{2}}+{{y}^{2}}-8x-2y-51=0\]
Correct Answer: D
Solution :
Required equation is \[(x-{{x}_{1}})(x-{{x}_{2}})+(y-{{y}_{1}})(y-{{y}_{2}})=0\] \[(x+4)(x-12)+(y-3)(y+1)=0\] \[{{x}^{2}}+{{y}^{2}}-8x-2y-51=0\].
You need to login to perform this action.
You will be redirected in
3 sec
