A) (1, ?3)
B) (?1, 3)
C) (1, 3)
D) None of these
Correct Answer: B
Solution :
Given that\[\frac{x+1}{2}=\cos \theta \]. Also \[\frac{y-3}{2}=\sin \theta \] \[\Rightarrow {{\left( \frac{x+1}{2} \right)}^{2}}+{{\left( \frac{y-3}{2} \right)}^{2}}=1\]\[\Rightarrow {{(x+1)}^{2}}+{{(y-3)}^{2}}=4\], whose centre is\[(-1,\ 3)\].
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