JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Equilibrium of Forces

  • question_answer
    If two forces of 5 N each are acting along X and Y axes, then the magnitude and direction of resultant is [DCE 2004]

    A)             \[5\sqrt{2},\,\,\pi /3\]

    B)               \[5\sqrt{2},\,\,\pi /4\]

    C)             \[-5\sqrt{2},\,\,\pi /3\]

    D)               \[-5\sqrt{2},\,\,\pi /4\]

    Correct Answer: B

    Solution :

                    \[|\overrightarrow{F}|=\sqrt{{{5}^{2}}+{{5}^{2}}}=5\sqrt{2}\ N.\] and \[\tan \theta =\frac{5}{5}\]=1   \[\Rightarrow \theta =\pi /4.\]


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