JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Equilibrium of Forces

  • question_answer
    Two forces of magnitude F have a resultant of the same magnitude F. The angle between the two forces is [CBSE PMT 1990]            

    A)                              \[45{}^\circ \]            

    B)                           \[120{}^\circ \]            

    C)                         \[150{}^\circ \]                     

    D)                         \[{{60}^{\text{o}}}\]

    Correct Answer: B

    Solution :

                                \[F=\sqrt{{{(F)}^{2}}+{{(F)}^{2}}+2F.F\cos \theta }\]Þ \[\theta =120{}^\circ \]            


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