JEE Main & Advanced Mathematics Binomial Theorem and Mathematical Induction Question Bank Expansion of binomial theorem

  • question_answer
    \[{{x}^{5}}+10{{x}^{4}}a+40{{x}^{3}}{{a}^{2}}+80{{x}^{2}}{{a}^{3}}\]\[+80x{{a}^{4}}+32{{a}^{5}}=\]

    A) \[{{(x+a)}^{5}}\]

    B) \[{{(3x+a)}^{5}}\]

    C) \[{{(x+2a)}^{5}}\]

    D) \[{{(x+2a)}^{3}}\]

    Correct Answer: C

    Solution :

    Conversely, \[{{(x+a)}^{n}}={{\,}^{n}}{{C}_{0}}+{{\,}^{n}}{{C}_{1}}{{x}^{n-1}}a+{{\,}^{n}}{{C}_{2}}{{x}^{n-2}}{{a}^{2}}+.....\] So, \[{{(x+2a)}^{5}}={{x}^{5}}+10{{x}^{4}}a+40{{x}^{3}}{{a}^{2}}+80{{x}^{2}}{{a}^{3}}+80x{{a}^{4}}+32{{a}^{5}}\].


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