| (i)\[{{1}^{3}}\] | (ii)\[{{4}^{0}}\] |
| (iii)\[{{0}^{4}}\] | (iv) \[{{3}^{1}}\] |
A) (i) and (ii)
B) (ii) and (iii)
C) (i) and (iii)
D) (i) and (iv)
Correct Answer: A
Solution :
\[{{1}^{3}}=1\times 1\times 1=1;\] \[{{4}^{0}}=1\] (Since any number to the power zero is one)
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