7th Class Mathematics Exponents and Power Question Bank Exponents and Powers

  • question_answer
    All the planets revolve around the Sun in elliptical orbits. Uranus's farthest distance from the Sun is approximately \[3.004\times {{10}^{9}}\text{ }km\]and its closest distance is approximately \[2.7499\times {{10}^{9}}km\]km. What is the average distance of Uranus from the Sun?       

    A)  \[(2.476\times {{10}^{9}})\,km\]                 

    B)  \[(2.8765\times {{10}^{9}})\,km\]                

    C)  \[(2.876\times {{10}^{8}})\,km\]               

    D)  None of these  

    Correct Answer: B

    Solution :

    Distance of Uranus from Sun \[=(3.004\times {{10}^{9}})\,km\] Uranus closest distance from Sun                         \[=(2.7499\times {{10}^{9}})\,km\] Total distance \[=3.004\times {{10}^{9}}+2.7499\times {{10}^{9}}\] \[=(5.753\times {{10}^{9}})\,km\] Average distance \[=\frac{5.753\times {{10}^{9}}}{2}\]                         \[=(2.8765\times {{10}^{9}})\,km\]


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