A) \[{{3}^{8}}\]
B) \[{{2}^{12}}\]
C) Both are equal.
D) Cannot be compared.
Correct Answer: A
Solution :
\[{{2}^{12}}={{2}^{3\times 4}}={{({{2}^{3}})}^{4}}={{8}^{4}}\] \[{{3}^{8}}={{3}^{2\times 4}}={{({{3}^{2}})}^{4}}={{9}^{4}}\] Since the powers of \[{{8}^{4}}\] and \[{{9}^{4}}\] are the same, \[{{9}^{4}}\] is greater than \[{{8}^{4}}\Rightarrow \,\,{{3}^{8}}>{{2}^{12}}\].
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