A) \[{{a}^{11}}{{b}^{18}}{{c}^{-15}}\]
B) \[{{a}^{11}}{{b}^{18}}{{c}^{15}}\]
C) \[{{a}^{-11}}{{b}^{-18}}{{c}^{15}}\]
D) \[{{a}^{-11}}{{b}^{18}}{{c}^{-15}}\]
Correct Answer: D
Solution :
\[\frac{a{{b}^{2}}{{c}^{3}}\times {{a}^{4}}\times {{b}^{5}}{{c}^{-6}}}{{{a}^{-7}}{{b}^{-8}}{{c}^{9}}\times {{a}^{10}}{{b}^{11}}{{c}^{-12}}\times {{a}^{13}}{{b}^{-14}}{{c}^{15}}}\]\[={{a}^{-11}}\,\,{{b}^{18}}\,\,{{c}^{-15}}\]
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