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7th Class Mathematics Exponents and Power Question Bank Exponents and Powers

  • question_answer
    Simplify \[\frac{{{64}^{2x}}\div {{16}^{x}}}{{{128}^{x}}\times {{4}^{2x}}}\].

    A)  \[{{2}^{-3x}}\]                   

    B)         \[{{2}^{8x}}\]

    C)  \[{{2}^{3x}}\]                   

    D)         \[{{2}^{11x}}\]

    Correct Answer: A

    Solution :

     \[\frac{6{{4}^{2x}}\div {{16}^{x}}}{{{128}^{x}}\times {{4}^{2x}}}=\frac{{{4}^{4x}}}{{{2}^{11x}}}=\frac{{{2}^{8x}}}{{{2}^{11x}}}={{2}^{-3x}}\]


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