A) Aryan
B) Ayan
C) Both of them
D) None of these
Correct Answer: C
Solution :
We have, \[{{\left( \frac{9{{a}^{3}}{{b}^{-8}}}{81{{a}^{-5}}{{b}^{2}}} \right)}^{-\frac{1}{2}}}={{\left( \frac{81{{a}^{-5}}{{b}^{2}}}{9{{a}^{3}}{{b}^{-8}}} \right)}^{\frac{1}{2}}}\] \[={{\left( 9{{a}^{-5}}{{a}^{-3}}{{b}^{2}}{{b}^{6}} \right)}^{\frac{1}{2}}}\] \[={{\left( 9{{a}^{-8}}{{b}^{10}} \right)}^{\frac{1}{2}}}=3\,{{a}^{-4}}{{b}^{5}}\]You need to login to perform this action.
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