A) \[200{{y}^{2}}-2=2(10y+1)\,(10y-1)\]
B) \[49{{x}^{2}}-36=(7x+6)\,(7x-6)\]
C) \[200{{y}^{2}}-2=2(10y+1)\,(10y+1)\]
D) \[36-100{{k}^{2}}=(6+10k)\,(6-10k)\]
Correct Answer: C
Solution :
\[200\,\,{{y}^{2}}-2=2\,\,(100{{y}^{2}}-1)\] \[=2\,\,[\,{{(10y)}^{2}}-{{1}^{2}}]\] \[=2\,\,[(10y+1)\,\,(10y-1)]\]
You need to login to perform this action.
You will be redirected in
3 sec
