A) \[2-32{{x}^{2}}=2{{(1-4x)}^{2}}\]
B) \[4{{x}^{2}}-49=(7-2x)\,(7+2x)\]
C) \[-18{{x}^{2}}+27x=9x(2x-3)\]
D) \[-25-150{{p}^{2}}=(-25)\,(1+6{{p}^{2}})\]
Correct Answer: D
Solution :
\[-25-150{{p}^{2}}=(-25)\,\,(1+6{{p}^{2}})\]
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