A) 35.5 gm
B) 17.75 gm
C) 71 gm
D) 142 gm
Correct Answer: B
Solution :
Equivalent of Cl deposited = No. of Faraday passed = 0.5 Wt. of \[Cl=0.5\times Eq.\,wt.\]\[=0.5\times 35.5=17.75\,\,gm\].You need to login to perform this action.
You will be redirected in
3 sec