A) 9650
B) 4825
C) 3860
D) 1930
Correct Answer: D
Solution :
\[C{{u}^{++}}+2{{e}^{-}}\to Cu\] \[{{E}_{Cu}}=\frac{63.54}{2}=31.77\] Amount of electricity required to deposit .6354 gm of Cu \[=\frac{96500\times 0.6354}{31.77}=1930\,Coulombs\].You need to login to perform this action.
You will be redirected in
3 sec