A) 100 K
B) 150 K
C) 195 K
D) 255 K
Correct Answer: B
Solution :
Given number of moles =1 Initial temperature \[={{27}^{o}}C=300K\] Work done by the system \[=3\,KJ=3000K\] It will be \[(-)\]because work is done by the system. Heat capacity at constant volume \[(Cv)=20\,J/k\] We know that work done \[W=-n{{C}_{V}}\,({{T}_{2}}-{{T}_{1}})\]; \[3000=-1\times 20\,\,({{T}_{2}}-300)\] \[3000=-20{{T}_{2}}+6000\] \[20{{T}_{2}}=3000\]; \[{{T}_{2}}=\frac{3000}{20}=150K\]You need to login to perform this action.
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