• question_answer A hydraulic jump is formed in a 5.0 wide rectangular channel with sequent depths of 0.2 m and 0.8 m. The discharge in the channel, in ${{\text{m}}^{\text{3}}}\text{/s,}$ is: A) 2.43                             B) 3.45C) 4.43                             D) 5.00

${{y}_{1}}=0.2\,m,$ ${{y}_{2}}=0.8\,m,$ $\frac{{{y}_{2}}}{{{y}_{1}}}=\frac{1}{2}\,\left[ \sqrt{1+8F_{1}^{2}-1} \right]$ $\frac{0.8}{{{y}_{1}}}=\frac{1}{2}\,\left[ \sqrt{1+8F_{1}^{2}-1} \right]$ $8=\sqrt{1+8F_{1}^{2}}-1$ $1+8F_{1}^{2}={{9}^{2}}=81$ $8F_{1}^{2}=80$ $F_{1}^{2}=80$ ${{F}_{1}}=3.16$ $F_{1}^{2}=\frac{v_{1}^{2}}{g{{y}_{1}}}$ $10=\frac{v_{1}^{2}}{9.81\times 0.2},$ $v_{1}^{2}=19.62$ ${{v}_{1}}=4.429\,\,\text{m/s}$ $Q=b{{y}_{1}}{{v}_{1}}=5\times 0.2\times 4.429\times 4.43\,{{\text{m}}^{\text{3}}}\text{/s}$