A) 1.0
B) 0.6
C) 0.3
D) 0.1
Correct Answer: D
Solution :
Displacement thickness, \[\delta '=\int\limits_{0}^{\delta }{\left( 1-\frac{u}{{{U}_{x}}} \right)}\,\,dy\] \[=\int\limits_{0}^{\delta }{\left[ 1-{{\left( \frac{y}{\delta } \right)}^{1/9}} \right]}\,\,dy\] \[=\left| y-\frac{1}{{{\delta }^{1/9}}}.{{y}^{10/9}}\times \frac{9}{10} \right|_{0}^{\delta }=\delta =\frac{9}{10}\,\delta =\frac{\delta }{10}\] \[\frac{\delta '}{\delta }=\frac{1}{10}=0.1\]
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