A) 1 : 2
B) 1 : 3
C) 2 : 3
D) 3 : 4
Correct Answer: D
Solution :
Weight of solid \[P,{{W}_{p}}=\] weight of water displaced \[=\frac{1}{2}\,\,{{V}_{p}}\times {{10}^{3}}\times 9.81\,N\] Weight of solid \[Q,\,{{W}_{Q}}=\frac{1}{2}\,{{V}_{Q}}\times {{10}^{3}}\times 9.81\,N\] \[{{\rho }_{P}}=\frac{{{W}_{p}}}{9.81\,{{V}_{p}}}=\frac{1}{2}\times {{10}^{3}}\] \[{{\rho }_{Q}}=\frac{{{W}_{Q}}}{9.81\,{{V}_{p}}}=\frac{1}{2}\times {{10}^{3}}\] \[\frac{{{\rho }_{p}}}{{{\rho }_{Q}}}=\frac{1}{2}\times \frac{3}{2}=\frac{3}{4}\] or 3 : 4
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