Answer:
\[{{m}_{{{T}_{1}}}}{{u}_{{{T}_{1}}}}+{{m}_{{{T}_{2}}}}{{u}_{{{T}_{2}}}}={{m}_{{{T}_{1}}}}{{v}_{{{T}_{1}}}}+{{m}_{{{T}_{2}}}}{{v}_{{{T}_{2}}}}\]
\[{{m}_{{{T}_{1}}}}{{u}_{{{T}_{1}}}}+{{m}_{{{T}_{2}}}}{{u}_{{{T}_{2}}}}={{m}_{{{T}_{1}}}}v+{{m}_{{{T}_{2}}}}v\]
\[\Rightarrow V=\frac{{{m}_{{{T}_{1}}}}{{u}_{{{T}_{1}}}}+{{m}_{{{T}_{2}}}}{{u}_{{{T}_{2}}}}}{{{m}_{{{T}_{1}}}}{{m}_{{{T}_{2}}}}}\]
\[=\frac{5004+1500\times 2}{500+1500}=\frac{2000+3000}{2000}\]
\[=\frac{5000}{2000}=2.5m/s\]
Truck \[({{T}_{1}})\]
Truck \[({{T}_{2}})\]
\[{{m}_{{{T}_{1}}}}=500kg\]
\[{{m}_{{{T}_{2}}}}=1500kg\]
\[{{u}_{{{T}_{1}}}}=4m/s\]
\[{{u}_{{{T}_{2}}}}=2m/s\]
\[{{V}_{{{T}_{1}}}}={{V}_{{{T}_{2}}}}=V=?\]
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