Answer:
\[{{m}_{A}}=m\] \[{{m}_{B}}=m\] \[{{V}_{A}}=V\] \[{{V}_{B}}=3V\] \[{{P}_{A}}:{{P}_{B}}=?\] as \[P=mv\] \[\therefore \,\,P\propto V\] [as mass is constant] so, \[\frac{{{P}_{1}}}{{{P}_{2}}}=\frac{{{V}_{1}}}{{{V}_{2}}}\Rightarrow \frac{{{P}_{1}}}{{{P}_{2}}}=\frac{V}{3V}\Rightarrow {{P}_{1}}:{{P}_{2}}=1:3\]
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