question_answer

Gravel is dropped into a conveyor belt at a rate of 0.5 kg/s. The extra force required in newton to keep the belt moving at 2 m/s is : (a) 1                                       (b) 2    (c) 4                                       (d) 0.5

Answer:

Given, the rate at which the gravel is dropped \[\left( \frac{m}{t} \right)=0.5kg/s\] Belt is moving with velocity \[(v)=2\text{ }m/s\text{ }F=?\] we know, \[F=v\times \left( \frac{m}{t} \right)\] \[\Rightarrow \] \[F=0.5\times 2=1\text{ }N\]