A) \[0.1\,\,N\]
B) \[0.3\,\,N\]
C) \[0.4\,\,N\]
D) \[0.5\,\,N\]
Correct Answer: C
Solution :
\[S=ut+\frac{1}{2}a{{t}^{2}}=0\times 2+\frac{1}{2}a\times 4=2a\] \[\Rightarrow \]\[a=2\,\,m\,\,{{s}^{-2}}\] \[F=ma=0.2\times 2=0.4\,\,N\]
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