9th Class Science Force and laws of motion Question Bank Force and Laws of Motion

  • question_answer
    In the first second of its flight, a rocket ejects 1 /40 of its mass with a velocity of \[1200\text{ }m\text{ }{{s}^{-1}}\]. The acceleration of the rocket is

    A) \[20\text{ }m\text{ }{{s}^{-2}}\]                

    B)        \[30\text{ }m\text{ }{{s}^{-2}}\]    

    C)        \[40\text{ }m\text{ }{{s}^{-2}}\]                

    D)        \[60\text{ }m\text{ }{{s}^{-2}}\]    

    Correct Answer: B

    Solution :

    Let m be the mass of the object. Ejected mass of the rocket \[=\frac{m}{40}\] According to the law of conservation of momentum, \[m{{u}_{1}}=\frac{m}{40}{{u}_{2}};at=\frac{{{u}_{2}}}{40};a=\frac{1200}{40\times 1}=30m{{s}^{-2}}\] \[(\because {{u}_{2}}=1200m\,\,{{s}^{-1}}\,\,and\,\,t=1\,\,\text{second)}\]


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