| Direction: Read the passage carefully and answer the following question. |
| An object of mass 1.5 kg travelling in a straight line with a velocity of \[5\text{ }m\text{ }{{s}^{-1}}\] collides with a wooden block of mass 5 kg resting on the floor. |
| This object sticks with wooden block after collision and both move together in a straight line. |
A) \[8.5\text{ }m\text{ }{{s}^{-1}}\]
B) \[9.5\text{ }m\text{ }{{s}^{-1}}\]
C) \[1.15\,\,m\,\,{{s}^{-1}}\]
D) \[1.5\,\,m\,\,{{s}^{-1}}\]
Correct Answer: C
Solution :
According to law of conservation of momentum, \[{{m}_{1}}{{v}_{1}}+{{m}_{2}}{{v}_{2}}=({{m}_{1}}+{{m}_{2}})v\] Or \[(1.5\times 5)+(5\times 0)=(1.5+5)v\] Or \[v=\frac{7.5}{6.5}=1.15m{{s}^{-1}}\] Thus, velocity of combination of these objects after collision is \[\text{1}\text{.15 m}\,\,{{\text{s}}^{\text{-1}}}\].
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