A) \[76\text{ }\times \text{ }13.6\text{ }\times \text{ }980\text{ }cm\] of mercury column
B) \[76\text{ }dyne\text{ }c{{m}^{-2}}\]
C) \[76\text{ }\times \text{ }13.6\text{ }cm\] of water column
D) \[76\text{ }\times \text{ }980\text{ }dyne\text{ }c{{m}^{-2}}\]
Correct Answer: A
Solution :
Standard atmospheric pressure is = \[76\times 13.6\times 980\text{ }cm\] of mercury column The correct answer is A.
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