Answer:
\[{{P}_{1}}=P\text{ }atm,\] \[{{P}_{2}}=5P\text{ }atm\] \[{{d}_{1}}=d\text{ }gm/lit.,\] \[={{d}_{2}}=?\] \[\Rightarrow \] \[\frac{{{P}_{1}}}{{{d}_{1}}}=\frac{{{P}_{2}}}{{{d}_{2}}}\Rightarrow {{d}_{2}}=\frac{{{P}_{2}}}{{{P}_{1}}}\times {{d}_{1}}\]______(a) \[{{d}_{2}}=\frac{5P}{P}\times d=5d\,gm/litre\]
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