A) \[3\times {{10}^{4}}\,newton\]
B) \[3\times {{10}^{2}}\,newton\]
C) \[3\times {{10}^{-2}}\,newton\]
D) \[3\times {{10}^{-4}}\,newton\]
Correct Answer: C
Solution :
\[F=Bil\sin \theta \] \[=500\times {{10}^{-4}}\times 3\times (40\times {{10}^{-2}})\times \frac{1}{2}=3\times {{10}^{-2}}N\]
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