JEE Main & Advanced Physics Magnetic Effects of Current / करंट का चुंबकीय प्रभाव Question Bank Force and Torque on a Current Carrying Conductor

  • question_answer
    A current of 10 ampere is flowing in a wire of length 1.5 m. A force of 15 N acts on it when it is placed in a uniform magnetic field of 2 tesla. The angle between the magnetic field and the direction of the current is            [MP PMT 1994]

    A)            \[30{}^\circ \]                      

    B)            \[45{}^\circ \]

    C)            \[60{}^\circ \]                      

    D)            \[90{}^\circ \]

    Correct Answer: A

    Solution :

               \[F=Bil\sin \theta \Rightarrow \sin \theta =\frac{F}{Bil}=\frac{15}{2\times 10\times 1.5}=\frac{1}{2}\]Þ \[\theta =30{}^\circ \]


You need to login to perform this action.
You will be redirected in 3 sec spinner