JEE Main & Advanced Physics Magnetic Effects of Current / करंट का चुंबकीय प्रभाव Question Bank Force and Torque on a Current Carrying Conductor

  • question_answer
    In hydrogen atom, the electron is making \[6.6\times {{10}^{15}}\,rev/\sec \] around the nucleus in an orbit of radius 0.528 Å. The magnetic moment \[(A-{{m}^{2}})\] will be [MP PET 1999]

    A)            \[1\times {{10}^{-15}}\]  

    B)            \[1\times {{10}^{-10}}\]

    C)            \[1\times {{10}^{-23}}\]  

    D)            \[1\times {{10}^{-27}}\]

    Correct Answer: C

    Solution :

                       \[i=6.6\times {{10}^{15}}\times 1.6\times {{10}^{-19}}=10.5\times {{10}^{-4}}amp\]                    \[A=\pi {{R}^{2}}=3.142\times {{\left( 0.528 \right)}^{2}}\times {{10}^{-20}}{{m}^{2}}\]                    Þ\[M=iA=10.5\times {{10}^{-4}}\times 3.142\times {{\left( 0.528 \right)}^{2}}\times {{10}^{-20}}\]                    \[=10\times {{10}^{-24}}units=1\times {{10}^{-23}}units\]


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