A) \[6.9\times {{10}^{-2}}amp-{{m}^{2}}\]
B) \[2.3\times {{10}^{-2}}amp\text{-}\,{{m}^{2}}\]
C) \[{{10}^{-2}}amp-{{m}^{2}}\]
D) \[{{10}^{-3}}amp-{{m}^{2}}\]
Correct Answer: A
Solution :
\[M=NiA=24\times 0.75\times 3.14\times {{(3.5\times {{10}^{-2}})}^{2}}\] \[=6.9\times {{10}^{-2}}A\text{-}\,{{m}^{2}}\]
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