A) Zero
B) IBL
C) 2IBL
D) \[\frac{1}{2}IBL\]
Correct Answer: A
Solution :
As shown in figure, since \[\overrightarrow{L}=0\] Hence according to \[\vec{F}=i(\vec{L}\times \vec{B})\] Þ \[\vec{F}=0\]You need to login to perform this action.
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