A) less than\[\frac{1}{3}\]
B) greater than \[\frac{1}{3}\]
C) equal to \[\frac{1}{3}\]
D) None of these
Correct Answer: B
Solution :
\[\frac{5}{3}+\frac{11}{4}-\frac{19}{5}\] \[=\frac{100+165-228}{60}=\frac{265-228}{60}\] \[\frac{37}{60}>\frac{1}{3}\]You need to login to perform this action.
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